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Theorem embed-and
⊦ a[hP0 ∧ hP1] = (a[hP0] ∧ a[hP1])
Type: A user defined theorem
Validity: The proof is valid.
Features: s,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 11
Used lemmas:
lift-aux
,
Used spec theorems:
heap-aux
/
mk-ext
heap-aux
/
apply
Used simplifier rules:
heap-sep
/heap-aux-inst/
and-com
heap-sep
/heap-aux-inst/
and-ass
heap-sep
/heap-aux-inst/
and
heap-sep
/
and-com
heap-sep
/
and-ass
heap-sep
/
and