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Theorem sep-inj3

⊦ hP0 = hP1 ∧ hP2 = hP3 ∧ hP4 = hP5 → hP0 * hP2 * hP4 = hP1 * hP3 * hP5

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

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Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 2
Used lemmas: sep-com, sep-ass,
Used spec theorems:
- Used simplifier rules: