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Theorem Sep-forall

∀ n0. n0 < m → nP0(n + n0) = nP1(n + n0) ⊦ nP0 ⊗_(n, m) = nP1 ⊗_(n, m)

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

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Infos about the proof

Proved?: Yes
Interactions: 5
Proof steps: 12
Used lemmas: Sep-rec, Sep-base,
Used spec theorems:
- Used simplifier rules: