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Theorem Sep-any

⊦ st ≠ ∅ → (((adP ⊗_ st * hP))(h) ↔ (∃ a, d, st0. ¬ a ∈ st0 ∧ st = st0[a, d] ∧ ((adP(a, d) * adP ⊗_ st0 * hP))(h)))

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