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Proof step 1 from proof bst-branch-strong (
previous step
)
⊦ bst(branch(t0, b, t1)) ↔ (∀ a. a ∈ t0 → a < b) ∧ (∀ a. a ∈ t1 → b < a) ∧ bst(t0) ∧ bst(t1)
Lemma
bst-branch