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Theorem bst-branch
⊦ bst(branch(t0, b, t1)) ↔ (∀ a. a ∈ t0 → a < b) ∧ (∀ a. a ∈ t1 → b < a) ∧ bst(t0) ∧ bst(t1)
Type: An axiom
Validity: The proof is valid.
Features:
Comment:
Used by:
bst-branch-rec
,
bst-elem-in-branch
,
bst-elem-order-left
,
bst-elem-order-right
,
butleftmost-bst
,
butleftmost-in
,
insert-bst
,
Used by units in proved state:
Proof exists?: