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Theorem array-exists-first-neq

⊦ ∃ n. n ≤ # ar0 ∧ n ≤ # ar1 ∧ subarray(ar0, 0, n) = subarray(ar1, 0, n) ∧ (n ≠ # ar0 ∧ n ≠ # ar1 → ar0[n] ≠ ar1[n])

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