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Proof step 42 from proof split-init-2 (previous step)

split(P, A, X), partitions(P, # A), ∀ p. p ∈ P → p.count = 0 ⊦ split(P, A, [])

User applied rule structural induction

And obtained the following new goals

Proof step 6:
split([], A, X), partitions([], # A), ∀ p. p ∈ [] → p.count = 0 ⊦ split([], A, [])

Rule argument

indvar:P

Additional information

[Concretesimprules((Csimpgen(partition freely generated by [], +;)))]