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Proof step 43 from proof split-init-2 (conclusion)

⊦ partitions(P, # A) ∧ split(P, A, X) ∧ (∀ p. p ∈ P → p.count = 0) → split(P, A, [])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
split(P, A, X), partitions(P, # A), ∀ p. p ∈ P → p.count = 0 ⊦ split(P, A, [])

Rule argument

Additional information

[Concretesimprules(())]