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Proof step 33 from proof ADD-lemma (previous step)

N = N0, V = V0, S2 = N ∧ S3 = V ∧ s0 = S ⊦ ⟪while s0 ≠ ∅ do choose w with w ∈ s0 in { s0 := s0 -- w ; if ¬ w ∈ S3 then S3 := S3 ++ w, S2 := S2 ++ w }⟫ (S2 = N0 ∪ (S \ V0) ∧ S3 = V0 ∪ S)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
S2 = N0, S3 = V0, s0 = S ⊦ ⟪while s0 ≠ ∅ do choose w with w ∈ s0 in { s0 := s0 -- w ; if ¬ w ∈ S3 then S3 := S3 ++ w, S2 := S2 ++ w }⟫ (S2 = N0 ∪ (S \ V0) ∧ S3 = V0 ∪ S)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]