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Theorem ADD-lemma
N = N0, V = V0 ⊦ ⟪ADD(S; V, N)⟫ (N = N0 ∪ (S \ V0) ∧ V = V0 ∪ S)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment: ADD essentially executes N := N ∪ (S \ V), V := V ∪ S.
Used by:
ADD-preserves-INV
,
ADD-preserves-INV-INVR
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 10
Proof steps: 29
Used lemmas:
decl-01
,
Used spec theorems:
set-union
/
subdef
set-union
/
ext
Used simplifier rules:
set-union
/
undel
set-union
/
diff-union
set-union
/
unindel
set-union
/
del-rax
set-union
/
Delete
set-basic
/
rax
nat-basic2
/
c
nat-basic2
/
a
nat-basic1
/
ref-1
nat-basic2
/
s
nat
/
ls-01
nat
/
lels-01
nat-basic1
/
one-01
set-basic
/
size-zero-02
set-union
/
del-size
set-union
/
sub-del-03
set-basic
/
ne-01
set-basic
/
sub-in
set-basic
/
In-empty
set-basic
/
size-zero
set-basic
/
size-zero-01
set-union
/
Difference
set-union
/
Union
set-union
/
uneq
set-union
/
diff-idem
set-basic
/
sub-idem
set-union
/
unc
set-basic
/
sub-e
set-union
/
une
set-union
/
una
set-union
/
diff-e