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Theorem decl-03

BFS (source, dest; norfail) { let V = {source} , C = {source} , N = ∅, n = 0, done = false in { while C ≠ ∅ ∧ ¬ done do { choose v with v ∈ C in if v = dest then done := true else { C := C -- v ; ADD(succ(v); V, N) } ; if C = ∅ then C := N, N := ∅, n := n + 1 } ; norfail := (done ⊃ some(n); fail) } }