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Proof step 5 from proof reachless-edge (previous step)

b ∈ succ(a), reach(source, a, m), m < n0 ⊦ # succ(a) = 0, succ(a) = ∅, ¬ n0 < m + 1 ∧ reach(source, b, m + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ reach(a, b, n + 1) ↔ (∃ c. reach(a, c, n) ∧ b ∈ succ(c))
Proof step 4:
b ∈ succ(a), reach(source, a, m), m < n0 ⊦ # succ(a) = 0, succ(a) = ∅, ∃ c. reach(source, c, m) ∧ b ∈ succ(c)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m])]]