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Proof step 6 from proof reachless-edge (previous step)

b ∈ succ(a), reach(source, a, m), m < n0 ⊦ # succ(a) = 0, succ(a) = ∅, ∃ m. ¬ n0 < m ∧ reach(source, b, m)

User applied rule exists right

And obtained the following new goals

Proof step 5:
b ∈ succ(a), reach(source, a, m), m < n0 ⊦ # succ(a) = 0, succ(a) = ∅, ¬ n0 < m + 1 ∧ reach(source, b, m + 1)

Rule argument

[EXRARG : pos: right 3, [extquanttermlist: (m + 1)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (m + 1)]]