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Proof step 89 from proof harness-1 (previous step)

⊦ 〈x := 1 ' + 3 ' + 3 ' + 2 '〉〈build_rec#(0; x, to)〉〈to0 := to ; if ¬ is_empty(x) then to0 := fail〉 to0 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 88:
x0 = 1 ' + 3 ' + 3 ' + 2 ' ⊦ 〈build_rec#(0; x0, to)〉〈to0 := to ; if ¬ is_empty(x0) then to0 := fail〉 to0 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]