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Proof step 90 from proof harness-1 (previous step)

⊦ 〈build#(1 ' + 3 ' + 3 ' + 2 '; to)〉 to = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

User applied rule call right

And obtained the following new goals

Proof step 1:
⊦
Proof step 89:
⊦ 〈x := 1 ' + 3 ' + 3 ' + 2 '〉〈build_rec#(0; x, to)〉〈to0 := to ; if ¬ is_empty(x) then to0 := fail〉 to0 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ()]]