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Proof step 12 from proof arr2list-get (previous step)

n < # ar, n ≤ m0 + 1, m0 + 1 < # ar, ∀ n, ar. n < # ar ∧ n ≤ m0 ∧ m0 < # ar → (arr2list(ar, m0)[n] ↔ ar[n]) ⊦ n = m0 + 1, (arr2list(ar, m0) + ar[m0 + 1] ')[n] ↔ ar[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
m0 + 1 < # ar, n < # ar, n ≤ m0, ∀ n, ar. n < # ar ∧ n ≤ m0 ∧ m0 < # ar → (arr2list(ar, m0)[n] ↔ ar[n]) ⊦ n = m0 + 1, (arr2list(ar, m0) + ar[m0 + 1] ')[n] ↔ ar[n]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m], [CSIMPSEQ : ⊦ m ≠ n → (m ≤ n ↔ m < n)], [CSIMPSEQ : ⊦ m + n = n + m])]]