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Proof step 13 from proof arr2list-get (previous step)

n < # ar, n ≤ m0 + 1, m0 + 1 < # ar, ∀ n, ar. n < # ar ∧ n ≤ m0 ∧ m0 < # ar → (arr2list(ar, m0)[n] ↔ ar[n]) ⊦ (arr2list(ar, m0) + ar[m0 + 1] ')[n] ↔ ar[n]

User applied rule cut formula

And obtained the following new goals

Proof step 6:
n = m0 + 1, n < # ar, n ≤ m0 + 1, m0 + 1 < # ar, ∀ n, ar. n < # ar ∧ n ≤ m0 ∧ m0 < # ar → (arr2list(ar, m0)[n] ↔ ar[n]) ⊦ (arr2list(ar, m0) + ar[m0 + 1] ')[n] ↔ ar[n]
Proof step 12:
n < # ar, n ≤ m0 + 1, m0 + 1 < # ar, ∀ n, ar. n < # ar ∧ n ≤ m0 ∧ m0 < # ar → (arr2list(ar, m0)[n] ↔ ar[n]) ⊦ n = m0 + 1, (arr2list(ar, m0) + ar[m0 + 1] ')[n] ↔ ar[n]

Rule argument

[fma-arg: n = m0 + 1]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (n = m0 + 1)]]