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Proof step 17 from proof RED-correct (previous step)

¬ 〈RED(t3; t'): kappa0 〉 t' = t1 ∨ t3 =>* t1 ∧ irred(t1), 〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), 〈RED(t3; t0): kappa0 〉 t0 = t1, t => t3, ¬ t =>* t1 ∨ t1 => t' ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 7:
〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), 〈RED(t3; t0): kappa0 〉 t0 = t1, t => t3, ¬ t =>* t1 ∨ t1 => t' ⊦ 〈RED(t3; t'): kappa0 〉 t' = t1
Proof step 16:
〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), 〈RED(t3; t0): kappa0 〉 t0 = t1, t => t3, ¬ t =>* t1 ∨ t1 => t', t3 =>* t1, irred(t1) ⊦

Rule argument

[CASEDARG : pos: left 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]