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Proof step 18 from proof RED-correct (previous step)

∀ t0, t2. ¬ 〈RED(t0; t'): kappa0 〉 t' = t2 ∨ t0 =>* t2 ∧ irred(t2), 〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), 〈RED(t3; t0): kappa0 〉 t0 = t1, t => t3, ¬ t =>* t1 ∨ t1 => t' ⊦

User applied rule all left

And obtained the following new goals

Proof step 17:
¬ 〈RED(t3; t'): kappa0 〉 t' = t1 ∨ t3 =>* t1 ∧ irred(t1), 〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), 〈RED(t3; t0): kappa0 〉 t0 = t1, t => t3, ¬ t =>* t1 ∨ t1 => t' ⊦

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (t3, t1)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (t3, t1)]]