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Proof step 37 from proof subst-KK-equal (previous step)

C1[K _ v1 _ v2] = C2[K _ v _ v0], context(C2), value(v0), value(v), value(v2), value(v1), value(t0), context(C1), ∀ v3, v4, C, v5, v6. C1[K _ v3 _ v4] = C[K _ v5 _ v6] ∧ value(v3) ∧ value(v4) ∧ value(v5) ∧ value(v6) ∧ context(C) → C1[v3] = C[v5] ⊦ C1[v1] = C2[v]

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 9, [extquanttermlist: (v1, v2, C2, v, v0) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (v1, v2, C2, v, v0)]]