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Theorem subst-KK-equal
C[K _ v1 _ v2] = C0[K _ v _ v0], value(v1), value(v2), value(v), value(v0), context(C0), context(C) ⊦ C[v1] = C0[v]
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
reduce
,
Proof exists?: Yes
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the proof
Infos about the proof
Proved?: Yes
Interactions: 8
Proof steps: 15
Used lemmas:
not-value
,
subst-Carg
,
substap-is-not-K
,
subst-Cfun
,
subst-O
,
Used spec theorems:
Used simplifier rules:
term
/
disj-01
value
/
val-K
context
/
ax-01
term
/
inj
context
/
ax-02
value
/
val-K-ap
context
/
context-O