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Proof step 31 from proof subst-SK-equal (previous step)

C1[S _ v3 _ v4 _ v5] = C2[K _ v _ v0], context(C2), value(v0), value(v), value(v5), value(v4), value(v3), context(C1), ∀ v1, v2, v6, C, v7, v8. C1[S _ v1 _ v2 _ v6] = C[K _ v7 _ v8] ∧ value(v1) ∧ value(v2) ∧ value(v6) ∧ value(v7) ∧ value(v8) ∧ context(C) → C1[v1 _ v6 _ (v2 _ v6)] = C[v7] ⊦ C1[v3 _ v5 _ (v4 _ v5)] = C2[v]

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 9, [extquanttermlist: (v3, v4, v5, C2, v, v0) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (v3, v4, v5, C2, v, v0)]]