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Theorem subst-SK-equal

C[S _ v3 _ v4 _ v5] = C0[K _ v _ v0], value(v3), value(v4), value(v5), value(v), value(v0), context(C0), context(C) ⊦ C[v3 _ v5 _ (v4 _ v5)] = C0[v]

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state: reduce,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 9
Proof steps: 17
Used lemmas: not-value-02, substap-is-not-K, not-value, subst-Carg, substap-is-not-S, subst-Cfun, subst-O,
Used spec theorems:
- Used simplifier rules: