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Proof step 13 from proof range-eq-ext (previous step)

ar0[n0] = ar1[n1], n1 + m0 < # ar1, n0 + m0 < # ar0, range=(ar0, n0 + 1, ar1, n1 + 1, m0), ∀ n. n < m0 → ar0[(n0 + 1) + n] = ar1[(n1 + 1) + n] ⊦ ∀ n. ¬ m0 < n → ar0[n0 + n] = ar1[n1 + n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
ar0[n0] = ar1[n1], n0 + m0 < # ar0, n1 + m0 < # ar1, range=(ar0, n0 + 1, ar1, n1 + 1, m0), n ≤ m0, ∀ n. n < m0 → ar0[(n0 + 1) + n] = ar1[(n1 + 1) + n] ⊦ ar0[n0 + n] = ar1[n1 + n]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)