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Proof step 14 from proof range-eq-ext (previous step)

ar0[n0] = ar1[n1], n0 + m0 < # ar0, n1 + m0 < # ar1, range=(ar0, n0 + 1, ar1, n1 + 1, m0), n ≤ m0, ∀ n. n < m0 → ar0[(n0 + 1) + n] = ar1[(n1 + 1) + n] ⊦ ar0[n0 + n] = ar1[n1 + n]

User applied rule constructor cut

And obtained the following new goals

Proof step 15:
ar0[n0] = ar1[n1], n = n2 +1, n1 + m0 < # ar1, n0 + m0 < # ar0, range=(ar0, n0 + 1, ar1, n1 + 1, m0), n ≤ m0, ∀ n. n < m0 → ar0[(n0 + 1) + n] = ar1[(n1 + 1) + n] ⊦ ar0[n0 + n] = ar1[n1 + n]

Rule argument

var: n

Additional information

Used simplifier rules: nat freely generated by 0, +1;;% ⊦ n + 0 = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic