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Proof step 10 from proof fle (previous step)

m < n, n ≤ n0, n0 ≤ m ⊦ n < n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
m < n0, n0 ≤ m ⊦ n0 = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ m < n ↔ ¬ n ≤ m;%anti: ⊦ m ≤ n → (n ≤ m ↔ m = n);%ler: ⊦ m ≤ m;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic