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Proof step 6 from proof fle (previous step)

m < n, n0 ≤ m, n ≤ n0, ¬ m < n0 → ¬ n < n0 ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 7:
m < n0, m < n, n ≤ n0, n0 ≤ m ⊦
Proof step 10:
m < n, n ≤ n0, n0 ≤ m ⊦ n < n0

Rule argument

pos: left 4

Additional information