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Theorem div-sum-ls

⊦ 0 ≤ i ∧ 0 ≤ i1 ∧ 0 < i + i1 ∧ 0 < j1 ∧ 0 < j2 ∧ 0 < j ∧ j1 < j ∧ j2 < j → (i * j1 + i1 * j2) / j < i + i1

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Infos about the proof