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Theorem mod-add-01
⊦ 0 < i ∧ j < 0 ∧ i ≤ abs(j) → (i + j) % i = j % i
Type: A user defined theorem
Validity: The proof is valid.
Features: simp,
Comment:
Used by:
mod-sub-01
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 3
Proof steps: 8
Used lemmas:
mod-zero-04
,
div-elim-negpos
,
Used spec theorems:
int-mult
/
modeqp-01
Used simplifier rules:
int-basic2
/
ls
int-abs
/
negle-07
int-abs
/
zero-gels-01
int-mult
/
succ-rmerge
int-abs
/
neg-13
int-abs
/
abs-08
int-abs
/
lels-02
int-basic2
/
add-zero
int-mult
/
Mult-zero
int-abs
/
anti
int-abs
/
lels
int-basic2
/
eq
int-mult
/
zero-eq
int-abs
/
numadd-01
int-basic2
/
add-a
int-basic2
/
add-c
int-mult
/
associativity
int-basic2
/
ls-01
int-mult
/
ls-dist-03
int-basic2
/
ls-02
int-basic1
/
forward-pos
int-abs
/
forward-le-05
int-mult
/
ls-forward
int-mult
/
zero-gr
int-abs
/
numls-02
int-abs
/
mone-06
int-mult
/
ls-same
int-abs
/
numls-03
int-abs
/
lels-04
int-abs
/
forward-le-04
int-abs
/
forward-lels
int-abs
/
forward-le-02
int-abs
/
zero-gels-03
int-mult
/
commutativity