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Theorem stutf-alltakenmax

⊦ stutf(nσ) ∧ ⌜m⌝ < # nσ ∧ n < nσ[m] → (∃ m0. m0 < m ∧ nσ[m0] = n ∧ nσ[m0 + 1] = n + 1)

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