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Theorem int2bytes-len-eq-pos

⊦ 0 ≤ i ∧ int2bytes(i).first = i2b(0) → (# int2bytes(i) = n ↔ 2 ^ ((n→i(n) - 1) * 8 - 1) ≤ i ∧ i < 2 ^ ((n→i(n) - 1) * 8) ∧ 0 < n)

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