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Theorem sqrt-exact-def
⊦ isSquare(dec) → sqrt(dec, i) = mkDecimal(sqrt(dec.int), dec.scale / 2)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
sqrt-exact-square
,
sqrt-isSquare
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 11
Used lemmas:
isSquare-isSquare
,
isSquare-scale
,
sqrt-even-precision-def
,
Used spec theorems:
int-square
/
sqrt-mult-squares
decimal
/
mkDecimal-enlarge
int-abs
/
Abs-pos
Used simplifier rules:
int-pot
/
isSquare-10pot
int-mult
/
commutativity
int-mult
/
associativity
int-pot
/
sqrt-10pot
int-abs
/
abs-03
int-div
/
abs
int-abs
/
abs-08
int-div
/
neg-01
int-abs
/
neg-15
int-basic2
/
add-a
int-basic2
/
add-c
decimal
/
scale-not-neg