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Theorem ls-fin-add
⊦ n→i(m) < n→i(n) + (* i) ∧ 0 ≤ i → m < n + i→n(i)
Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 4
Proof steps: 15
Used lemmas:
nat2int-04
,
sub
,
i2i-pos
,
rax-04
,
n2i-add
,
nat2int-08
,
num-i2n-le-02
,
ls-int-ls-nat
,
num-n2i-ls-02
,
nat2int-03
,
abs-zero
,
pos-int
,
Used spec theorems:
Used simplifier rules:
int-abs
/
zero-gels-04
int-abs
/
forward-le-01
nat
/
lels
nat
/
lez-01
nat-basic
/
z-01
nat-basic
/
a
nat-basic
/
c
int-basic2
/
add-a
int-basic2
/
add-c
nat-basic
/
succ
nat-basic
/
refl-nat
nat-basic
/
s-04
nat
/
les
nat-basic
/
oz
nat-basic
/
lf-01
nat-basic
/
f
nat
/
eqle-one
nat
/
le-def
nat-basic
/
l-02
nat-basic
/
zero
int-abs
/
forward-lsle
int-abs
/
forward-le
int-abs
/
lels
nat
/
pred-03
int-abs
/
leone
int-abs
/
anti
nat-basic
/
add-base
int-basic2
/
add-zero-rev
nat-basic
/
lf-02
nat
/
ls-le-simp
nat
/
eq-02
int-basic2
/
ls-01
int-basic2
/
ls
nat-basic
/
eq-01
int-basic1
/
lf-02
nat
/
elim-pred-c
int-abs
/
lels-02
int-abs
/
numadd-01
int-abs
/
succ-02
int-abs
/
numls-01
int-basic2
/
succ-01
int-abs
/
numls-02
int-abs
/
mone-06
int-basic1
/
irref
int-abs
/
forward-le-05
int-basic2
/
lst-04
int-abs
/
sub-ls-01
int-abs
/
sub-pred
int-abs
/
sub-add-01
int-abs
/
sub-eq
int-abs
/
forward-le-04
int-basic2
/
lst-03
nat
/
add-num-01