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Theorem sublist-append-04
⊦ n + n0 + n1 ≤ # x → sublist(n, n0, x) + sublist(n + n0, n1, x) = sublist(n, n0 + n1, x)
Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 19
Used lemmas:
restN-rec
,
firstN-rec
,
first-num
,
rest-rec
,
firstN-zero
,
restN-zero
,
sublist-def
,
Used spec theorems:
Used simplifier rules:
list-data
/
size-nil
nat
/
lez-01
nat-basic
/
z-01
list
/
Nil
list
/
a
nat-basic
/
a
nat-basic
/
c
list
/
len-02
list
/
len
list
/
c
nat-basic
/
z-02
nat-basic
/
zero
list
/
c-07
nat
/
pred-03
list
/
c-08
nat
/
elim-pred-c
nat
/
lep-02
nat-basic
/
oz
list
/
app-01
nat-basic
/
eq-01
nat-basic
/
add-base