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Proof step 10 from proof subst-KK-equal (previous step)

C0 = C _ t, K _ v1 _ v2 = C0[K _ v _ v0], value(v1), value(v2), value(v), value(v0), context(C0) ⊦ v1 = C0[v]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ (C _ t1)[t] = C[t] _ t1
Proof step 9:
K _ v1 = C[K _ v _ v0], context(C), value(v0), value(v), value(t), value(v1) ⊦ v1 = C[v] _ t

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ context(C _ t) ↔ context(C)], [CSIMPSEQ : ⊦ t _ t0 = t1 _ t2 ↔ t = t1 ∧ t0 = t2])]]