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Proof step 9 from proof subst-KK-equal (previous step)

K _ v1 = C[K _ v _ v0], context(C), value(v0), value(v), value(t), value(v1) ⊦ v1 = C[v] _ t

User applied rule constructor cut

And obtained the following new goals

Proof step 4:
⊦ O[t] = t
Proof step 5:
⊦ (C _ t1)[t] = C[t] _ t1
Proof step 6:
⊦ C[t _ t0] ≠ K
Proof step 7:
⊦ (t1 _ C)[t] = t1 _ C[t]
Proof step 8:
⊦ ¬ value(C[K _ t _ t0])

Rule argument

[var-arg: C]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : rawctxt generated by o, _, _;], [CSIMPSEQ : ⊦ t _ t0 ≠ K], [CSIMPSEQ : ⊦ t _ t0 = t1 _ t2 ↔ t = t1 ∧ t0 = t2], [CSIMPSEQ : ⊦ context(t _ C) ↔ ¬ ¬ (context(C) ∧ value(t))], [CSIMPSEQ : ⊦ value(K)])]]