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Theorem numadd

⊦ i + (* j) = i0 + (* j0) ↔ i = i0 + (j0 - j)

Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by: abs-04, k-sub-rec1, minus, sub-add-02, sub-add-03, sub-add-07, sub-sub-02,
Used by units in proved state: int-mult, int-pot, int-div, intnat, int-min,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 2
Used lemmas: sub-eq, sub-add-01,
Used spec theorems:
- Used simplifier rules:
  - int-basic2/add-c
  - int-basic2/add-a