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Theorem sub-add-01
⊦ i + (j - i0) = i + j - i0
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
abs-sub-02
,
abs-succ
,
absa
,
absls-05
,
absone-01
,
abssub-03
,
abssub-04
,
ex-le-add
,
k-sub-rec1
,
k-sub-rec2
,
le-sub-same
,
ler
,
minus-01
,
minus-02
,
minus-ass
,
minus-neg
,
minus-rew
,
minus-sub
,
mone-01
,
neg-15
,
negone
,
num-eq-shift
,
num-subadd
,
numadd
,
numle-01
,
numls-01
,
numsub
,
one-03
,
ple-01
,
sub-add-04
,
sub-add-05
,
sub-add-07
,
sub-add-08
,
sub-eq
,
sub-ls-02
,
sub-minus
,
sub-pred
,
sub-shift
,
sub-shift-second
,
sub-sub
,
sub-sub-01
,
sub-sub-02
,
sub-sub-04
,
sub-zero
,
Used by units in proved state:
int-mult
,
int-pot
,
int-gcd
,
int-div
,
intnat
,
int-square
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 0
Proof steps: 1
Used lemmas:
sub-add
,
elim-sub
,
Used spec theorems:
Used simplifier rules:
int-basic2
/
add-a
int-basic2
/
add-c
int-basic2
/
add-in