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Theorem byte-law-add-one
⊦ i2b(i + j) = i2b(b2i(i2b(i)) + j)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
byte-law-add
,
byte-law-sub-one
,
byte-law-sub-one-01
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 10
Proof steps: 19
Used lemmas:
byte-in
,
bib-upper
,
byte
,
byte-mult
,
byte-add-256
,
bib-in-01
,
bib-lower
,
byte-mult-256
,
byte-law-add-pos
,
Used spec theorems:
int-div
/
modex
Used simplifier rules:
int-abs
/
elim-sub
int-basic1
/
numlslsdel-01
int-basic1
/
forward-pos
int-abs
/
sub-add-01
int-abs
/
numlelsdel
int-abs
/
forward-le-05
int-abs
/
zero-gels-04
int-mult
/
zero-ge-add
int-div
/
mod-zero-01
int-div
/
div-elim-pospos
int-abs
/
forward-le-01
int-abs
/
forward-lsle
int-abs
/
lels-04
int-basic2
/
add-zero
int-abs
/
numleledel-01
int-basic1
/
lst
int-abs
/
forward-lels
int-abs
/
numlsledel-01
int-abs
/
numlelsdel-01
int-abs
/
forward-le-04
int-abs
/
numls-02
int-abs
/
neg-13
int-abs
/
abs-08
int-abs
/
zero-gels-03
int-basic2
/
add-c
int-basic2
/
add-a
int-mult
/
commutativity
int-mult
/
associativity
int-div
/
mod-ls-zero
int-abs
/
lels
int-abs
/
lels-03
int-div
/
div-elim-negpos
int-abs
/
forward-le-02
int-abs
/
zero-gels-01
int-abs
/
lels-01