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Theorem int2int-lastn-negpos

⊦ i < 0 ∧ ¬ lastn(m, int2bits(i)).first ∧ m ≤ # int2bits(i) ∧ m ≠ 0 ∧ i % 2 ^ n→i(m) ≠ 0 → bits2int(lastn(m, int2bits(i))) = i % 2 ^ n→i(m) + 2 ^ n→i(m)

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