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Theorem div-add1-negpos-neg-02

⊦ i % j = 0 ∧ i + i0 < 0 ∧ i < 0 ∧ 0 ≤ i0 ∧ 0 < j → (i + i0) / j = i / j + (i0 + (j - 1)) / j

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